Answer Key: Conservation of Mass in Chemical Reactions
How to use this key
Answers are grouped by section and question number. Many items are open-ended; accept any response that shows correct reasoning even if the wording differs. The mass calculations are worked out in full. Notes flag where more than one answer is defensible and list common misconceptions to watch for. A calculator is allowed but not required โ all values divide and subtract cleanly. Estimated grading time: ~6โ8 min per packet.
Start Notice & Wonder grade for effort ยท ~2 min
1 Where did the burned wood's material go?
2 Capped bottle before vs. after fizzing.
Build Read the Science ~1 min
3 Atom counts from Figure 1; were atoms conserved?
Apply Use the Data ~3 min
4 Check conservation in Reaction 1 (worked).
5 Find the missing mass, Reaction 2 (worked).
5b. 15.0 g + (mass of B) = 40.0 g โ mass of B = 40.0 g โ 15.0 g = 25.0 g. Reactant B had a mass of 25.0 g. (Closed system, so all product mass came from the reactants.)
6 Explain the open system, Reaction 3 (worked).
6b. The 16.0 g was not destroyed. In this open beaker a gas product formed and escaped into the air, carrying those 16.0 g away where the balance could not weigh them. If the reaction had been done in a closed container, the trapped gas would have been weighed and the total would still be 50.0 g. The law of conservation of mass holds โ the atoms left as gas rather than being destroyed. Full credit for identifying escaping gas as the missing mass and stating the law is not broken.
7 Count atoms to check the balance: CH4 + 2 O2 โ CO2 + 2 H2O.
| Element | Left (reactants) | Right (products) | Balanced? |
|---|---|---|---|
| Carbon (C) | 1 (in CH4) | 1 (in CO2) | yes |
| Hydrogen (H) | 4 (in CH4) | 4 (2 ร 2 in 2 H2O) | yes |
| Oxygen (O) | 4 (2 ร 2 in 2 O2) | 4 (2 in CO2 + 2 in 2 H2O) | yes |
8 Observation (O) vs. Inference (I).
b) I โ the 16.0 g of escaped gas is not a recorded value; it is reasoned out (50.0 โ 34.0) using conservation of mass.
c) O โ a value read directly (20.0 g product).
d) I โ a conclusion reasoned from the law (25.0 g of B is calculated, not measured; the table shows a dash).
Observation = measured/read directly; inference = a conclusion reasoned from evidence.
9 Closed vs. open โ which is fair?
Explain CER (Q10) ~2 min
10 Was mass conserved in Reaction 1?
Defensible alternates: A student may cite the closed-system condition as a piece of evidence, or contrast Reaction 1 with the open Reaction 3. Accept any claim of "conserved" supported by two correct numeric mass values and sound conservation-of-mass reasoning. A claim of "not conserved" is incorrect for Reaction 1 (the masses are equal) and should not earn full credit.
CER scoring rubric (3 points)
| Score | Claim | Evidence | Reasoning |
|---|---|---|---|
| 3 | Clear, correct claim: mass was conserved in Reaction 1. | Two accurate mass values from Table 1 (e.g., 12.0 + 8.0 g reactants and 20.0 g product). | Correctly uses conservation of mass / rearranged atoms and the closed system to explain why reactant mass = product mass. |
| 2 | Correct claim stated, mostly clear. | One solid mass value, or two with a minor error. | Some correct linkage but incomplete or a small misconception. |
| 1 | Vague or partly correct claim. | Evidence weak, non-numeric, or not from the table. | Little or flawed reasoning; law not correctly applied. |
| 0 | No claim, or an incorrect "not conserved" claim. | No evidence. | No reasoning. |
Close ACE ~1 min
ACE Articulate / Connect / Extend.
Connect: the cited row must show conservation or an apparent change, e.g., Reaction 1: 12.0 + 8.0 g = 20.0 g product (conserved), or Reaction 3: 50.0 g โ 34.0 g solid (16.0 g left as gas).
Extend: any correct new example, e.g., a rusting nail gains mass because iron takes in oxygen gas from the air; a fizzing open soda loses mass because carbon dioxide gas escapes; a burning candle in open air seems to lose mass but the atoms leave as gases. More than one answer is defensible; the key is that atoms are conserved and only the weighable mass changed.
Extend Early finisher & block extension (optional)
EF Design your own conservation problem.
Block Balance H2 + O2 โ H2O with coefficients (worked).
| Element | Left | Right |
|---|---|---|
| H | 2 ร 2 = 4 | 2 ร 2 = 4 |
| O | 1 ร 2 = 2 | 2 ร 1 = 2 |
Watch Common misconceptions
- "Mass (or matter) is created or destroyed in a reaction." Atoms are never created or destroyed โ they are only rearranged. New substances form, but the same atoms are present before and after, so the total mass is unchanged.
- "Gases have no mass / don't count." Gases have mass just like solids and liquids. In Reaction 3 the "missing" 16.0 g is the mass of the escaped gas. Watch for students who ignore gas when checking conservation.
- "An open-system mass loss (or gain) breaks the law." The law still holds; the container simply cannot weigh matter that has left as gas (mass seems to drop) or been pulled in from the air (mass seems to rise). A closed system reveals the true conservation.
- Confusing coefficients and subscripts (Q7, Block). A coefficient (big number in front) multiplies the whole particle; a subscript (small low number) counts atoms inside one particle. In 2 H2O the atoms are 2 ร 2 = 4 H and 2 ร 1 = 2 O.
- Observation vs. inference (Q8). Students often mark a calculated value (escaped gas, missing reactant) as an "observation." If a number is reasoned out with the law rather than read from the table, it is an inference.
Teacher follow-up based on likely errors
If many students say mass was destroyed in the open beaker (Reaction 3), do a quick 5-minute discussion contrasting a sealed bottle with an open one and point to the escaped gas. If the missing-mass subtraction in Q5 is shaky, model reactants = products aloud with units. If Q7 atom counts are off, review that a coefficient multiplies the whole formula while a subscript counts atoms inside it. If CER (Q10) evidence is non-numeric, model citing the 12.0 + 8.0 = 20.0 g contrast. The "mass is destroyed" and "gas has no mass" misconceptions are the highest-value items to address next class.